Interactive solution for Capybara Quiz 0% Question 1 of 12 1. In this problem, the motion of how many bodies needs to be studied?NoneThreeOneTwo Loading... Question 1 of 12Question 2 of 12 2. Which of the following are the horizontal and the vertical types of motion of the capybara?Uniform accelerated motion horizontally and non-uniform accelerated motion verticallyConstant velocity motion horizontally and Non-uniform accelerated motion verticallyConstant velocity motion horizontally and uniform accelerated motion verticallyConstant velocity motion horizontally and constant velocity motion verticallyUniform accelerated motion horizontally and uniform accelerated motion vertically Loading... Question 2 of 12Question 3 of 12 3. Select all the variables of the problem that are knownThe horizontal accelerationThe vertical accelerationThe vertical displacement The initial velocityThe minimum horizontal displacement Loading... Question 3 of 12Question 4 of 12 4. Take \(x\) to be the horizontal position and \(y\) the vertical position. Which of the following equations are relevant in this exercise? (Hint: The equations should be not only correct but also useful.)\(x_f=x_i+v_{ix}t\)\(v_{fy}=v_{iy}+a_yt\)\(y_f=y_i+v_{iy}t+\frac{1}{2}a_yt^2\)\(x_f=x_i+v_{ix}t+\frac{1}{2}a_xt^2\)\(y_f=y_i+v_{iy}t\) Loading... Question 4 of 12Question 5 of 12 5. We can take the horizontal motion equation, solve for \(v_{ix}\), and replace the numerical values. We don't need any more equations nor algebra.TrueFalse Loading... Question 5 of 12Question 6 of 12 6. The time of the vertical motion and the horizontal motion is the same.TrueFalse Loading... Question 6 of 12Question 7 of 12 7. Take the following coordinate system: Take the previous equation for vertical motion with \(H\) the height of the mound, \(L\) the creek's width, and \(g\) the gravity acceleration; then, solve for \(t\). Which of the following equations is equivalent to yours?\(t = \sqrt{\frac{gL}{2H}}\)\(t = \sqrt{\frac{2H}{g}}\)\(t = \sqrt{-\frac{2H}{g}}\)\(t = \sqrt{\frac{2L}{g}}\) Loading... Question 7 of 12Question 8 of 12 8. Which of the following conditions best represents the minimum initial speed of the capybara to get to the other side of the creek?\(y_f = v_{iy} t > L\)\(x_f = v_{ix} t > H\)\(x_f = v_{ix} t > L\)\(x_f = v_{ix} t < L\) Loading... Question 8 of 12Question 9 of 12 9. Take the previous conditions and the following coordinate system: Connect the correct values to the variables.\(x_f\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect\(y_f\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect\(x_i\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect\(y_i\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect\(v_{ix}\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect\(v_{iy}\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect\(a_{y}\) L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselectextra L = 2 m UnselectH = 3 mUnselectg = 9.8 m/s\(^2\)Unselect0 mUnselect0 m/sUnselectUnknownUnselect0 mUnselectg = -9.8 m/s\(^2\)Unselect Loading... Question 9 of 12Question 10 of 12 10. Replace the time equation we found before in the inequation of the minimum initial speed condition. Take this minimum value as \(v_{ix}^{min}\). Which of the following equations is equivalent to yours?\(v_{ix}^{min}=L\sqrt{\frac{g}{2H}}\)\(v_{ix}^{min}=L-\sqrt{\frac{2H}{g}}\)\(v_{ix}^{min}=L\sqrt{\frac{2H}{g}}\)\(v_{ix}^{min}=\sqrt{\frac{2H}{g}}\)-L Loading... Question 10 of 12Question 11 of 12 11. Select the statements that are true.If the initial speed of the capybara remains constant and the creek width increases, the height of the mound should increase as well for the capybara to get to the other side. The gravity is not important for the capybara to arrive on the other side of the creek. The minimum initial speed of the capybara to get to the other side of the creek safely must increase if the mound's height increases. The minimum initial speed of the capybara to get to the other side of the creek safely must increase if the creek's width increases. Loading... Question 11 of 12Question 12 of 12 12. Replace the values of the variables in the last equation we found. The minimum initial speed the capybara needs to get safely to the other side of the creek is m/s. Loading... Question 12 of 12 Loading... sebasmurgue2021-08-12T21:56:37-04:00 Related Posts Leaderboard Global November 11th, 2021 | 0 Comments PHY146 Assignments October 6th, 2021 | 0 Comments Latex issues with WPML September 9th, 2021 | 0 Comments Interactive Electric Plane September 7th, 2021 | 0 Comments Darts Quiz August 14th, 2021 | 0 Comments Leave A Comment Cancel replyComment Save my name, email, and website in this browser for the next time I comment. Notify me of follow-up comments by email. Notify me of new posts by email. Δ
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